2007-06-05 08:11:51 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x² - 25 = 0
x² - 25 + 25 = 0 + 25
x² = 25
√x² = ± √25
x = ± 5
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2007-06-05 08:17:23 · answer #1 · answered by SAMUEL D 7 · 1⤊ 1⤋
the square root of x^2-25=square root of(x-5)(x+5)
2007-06-05 15:17:06 · answer #2 · answered by pioneers 5 · 1⤊ 0⤋
The factors of the expression
x^2 - 25
are
(x + 5)(x - 5)
but this answer does not give you a square root.
2007-06-05 15:18:40 · answer #3 · answered by kindricko 7 · 0⤊ 0⤋
no special form of square root since X^2-25 =(x-5) (x+5) it is not a perfect square only pf x have a specific value
exemple x =13 then x^2-25 =169 -25 = 144 (square of 12)
2007-06-05 15:16:09 · answer #4 · answered by maussy 7 · 1⤊ 0⤋
Though x² - 25 does factor into (x + 5)(x - 5), the square root by itself of this quantity doesn't really simplify at all.
â[x² - 25] = â[(x + 5)(x - 5)].
2007-06-05 15:19:37 · answer #5 · answered by Louise 5 · 1⤊ 0⤋
The value of sqrt(x^2 - 25) depends on the value of x. If we write sqrt(x^2 - 25)
as sqrt[ (x + 5)(x - 5) ], then we can see that the domain of sqrt(x^2-25) is any
number x such that x < -5 or x > 5.
So, once we choose some value of x from the domain of sqrt(x^2 - 25), then we can evaluate sqrt(x^2 - 25) at that value of x.
2007-06-05 15:25:30 · answer #6 · answered by mathjoe 3 · 1⤊ 0⤋
1/the square root of x^23
2007-06-05 15:16:20 · answer #7 · answered by Super Duper 2 · 0⤊ 2⤋
x^2 +5x-5x-25
(x+5)(x-5)
so its square root of [(x+5)(x-5)]
2007-06-05 15:16:50 · answer #8 · answered by sweet n simple 5 · 1⤊ 0⤋
(x-5)(x+5)
2007-06-05 15:14:34 · answer #9 · answered by Anonymous · 0⤊ 5⤋