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Given triangle ABC with side a = 12, side b = 10 and side c = 8, find the angles and put them in minutes.

2007-06-05 07:14:10 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

To figure this out, you need to use the law of cosines. Unfortunately, this side lengths for this triangle do not form a Pythagorean triple, so ABC is not a right triangle. That's why you have to use the law of cosines. The law of cosines is as follows:

c^2 = a^2 + b^2 -2*a*b*cos(θ) where θ is the angle opposite of side c.

Here are the calculations for the angle across from side a. In this case, side a of ABC is "c" from the equation.

c^2 = a^2 + b^2 -2*a*b*cos(θ)
12^2 = 10^2 + 8^2 -2*10*8*cos(θ)
It doesn't matter which side corresponds to "a" or "b," you will get the same answer regardless of the order.
144 = 100 + 64 - 160*cos(θ)
-20 = -160*cos(θ)
1/8 = cos(θ)
θ = 82.8 degrees = 4969 minutes

Do this for all the sides (switching side b and c for "c" in the equation). Once you find θ (in degrees) with a calculator, multiply by 60, and you will convert your angle values to minutes. The answers I got are 82.8 degrees (4969') across of side a, 55.8 degrees (3346') across of side b, 41.4 degrees (2485') across of side c.

2007-06-05 07:19:55 · answer #1 · answered by PhysicsPat 4 · 0 0

Hi. Well, the total will be 180 degrees. Times 60 equals the total minutes. Hint. Break the triangle into two right triangles and use your friend Pythagoras.

2007-06-05 07:18:26 · answer #2 · answered by Cirric 7 · 0 1

because you have already got an a interior the equation, enable ok stand for section ok= a million/2·a·b sin C ok= a million/2·18·10 sin 40 5 ok= a million/2·a hundred and eighty sin 40 5 ok= ninety sin 40 5 Now use your calculator to multiply ninety via the sin of 40 5 (type 40 5 and press the sin button on the calculator) ok(section)=sixty 3.6

2016-11-26 01:31:26 · answer #3 · answered by Anonymous · 0 0

72 and 60 and 48 degrees

4320 and 3600 and 2880 minutes

2007-06-05 07:36:01 · answer #4 · answered by Anonymous · 0 1

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