what is e=mc ^2 if m=762 and c^2=2?

Question

i dont know if thats a coherent question lol but i tried, thx if you can figure it out

Answer 1

u cant change the value of a constant!!!!!!!
but if velocity was 2 then u could calculate the kinetic energy of the body using the classical physics formula
K.E.=1/2m(v^2)
but the rest energy of the body would still be
E=762(c^2)

Answer 2

If m = 762 and c^2 = 2 then it's e = (762) (2). e = 1524

Answer 3

c is always constant as it stands for the speed of light in vacuum (3 * 10^8 m/s). m means mass of an object in kg. e stands for energy (in joules). c^2 cannot be 2. I'll solve it taking c = 3 * 10^8 m/s

e = (762 * 300000000^2) joules
e = 68580000000000000000 joules

You can see how much energy we get if an object of mass 762 kg is completely converted into energy.

Answer 4

Scenario -I :
E=MC^2 is an energy eqn.
C= Speed of Light, which unversally constant(299,792,458 m/s.). hence the value of E for if m=762 will b
e=(762)*(299,792,458) m/s.
i.e, e=228,441,852,996 joules.

Scenario-II
e=762*2
i.e, e=1524

so the former is de Physics based on Proven theory
later is the physics based on Assumptions.

Answer 5

E=1077.63 You square root the 2 and time it by 762. So the mass converted into that much energy.

Answer 6

2(762)=1524

Answer 7

e=mc^2
=762*2
=1524
i have assumed c^2 =2 because you have not given its units
if you gave its units i will object

Answer 8

The equation e=mc^2 refers to an equivalent energy (e) that can be obtained from a mass (m) . The c refers to the speed of light, which is a constant (186, 000 miles per second).

Answer 9

1524

Answer 10

hey in this formula c is the speed of light of c = 3 x 10 ^8 m / sec

so we have to calculate this

mc^2
762 x (3 x10^8) ^ 2