is this a polynomial?

Question

5. (x) + 12
---right before the x there is a square root sign, i couldnt figure out how to right it----

A This is not a polynomial because the variable is underneath a square root sign.
B This is not a polynomial because it does not contain x2
C This is not a polynomial because the exponents are not divisible by 2.
D This is a polynomial because it contains no negative exponents.
E This is a polynomial because there are no variables in the denominator.
F This is not a polynomial because the x has no positive coefficient.

Answer 1

Actually, none of the answers is accurate. It is indeed a polynomial because it's a function of the form a_0 + a_1 x....+a_n x^n, where the exponents are integers 0,1,2...n.

In this case, it's a polynomial of degree 1. (n =1)

Edit
Sorry, I misread your question, didn't get the square root sign. So, it's not a polynomial because it's not a function like the one above.

Answer 2

A.

Because sqrt(x) alone already determines that the equation is not a polynomial. A polynomial should look something like..

a + bx + cx^2 + dx^3 + ex^4 ... etc,
where a, b, c, d, e, etc are constants (can also be zero)

Answer 3

I think it is b. Because you need x^2 to factor out a polynominal.
Example : (x-3) (x+4)

Answer 4

Answer is A.

(All other things can be true for polynomials.)