Please help with this question?

0 ⤊

Let (x + y)^4 = 3x. Determine dy/dx.

a) [¾(x+y)^3] – 1
b) [3√3/4] – 1
c) 3/(x + y)^4
d) ¾(x + y)^3

2007-06-05 04:50:38 · 2 answers · asked by learning.to_swim 1 in Science & Mathematics ➔ Mathematics

By implicit differentiation
4(x+y)^3 (1+y´)=3
3/4((x+y)^(-3)-1=y´=dy/dx
It seams like a) but the exponent is (-3)

2007-06-05 09:28:24 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋

4(x+y)^3 (dx+dy)=3 dx
3/4 (x+y)^(-3)=1+dy/dx
dy/dx= 3/4 (x+y)^(-3) -1
the answer is (a)

2007-06-09 00:54:00 · answer #2 · answered by B 2 · 0⤊ 0⤋