algebra 2 help?

Question

state the domain and range
y = (x^2)/(x^2-16)

Answer 1

tycha almost got it the range is negative infinity to 0 and 1 to positive infinity....here's why....the graph has a horizontal asymptote at y=1 so when the graph comes down from positive infinity it never crosses below y=1

Inbetween x=-4 and x=4 the graph kinda looks likes a parabola pointing down to negative infinity but it never goes higher than y=0 because the x^2 in the denominator will always be smaller that the -16 so the function will never yield a positive answer in that region.

Answer 2

Domain everthing except -4 and 4 so the denominator<>0
range everything except 16?

Answer 3

The domain, as stated, is all real numbers except -4 and 4. The range is all real numbers. x approaches -4 from the positive, y goes to negative infinity. As x approaches -4 from the negative, y goes to positive infinity.

f(-3.999) = -1999.25
f(-4.001) = 2000.75

The reverse is true as x approaches 4.
f(3.999) = -1999.25
f(4.001) = 2000.75

As x gets more positive when x is greater than 4, y goes to 1 from the positive side.

f(16) = 1.067
f(20) = 1.042

The same is true when x < -4

f(-16) = 1.067
f(-20) = 1.042

Answer 4

yeah, i just got done with college algebra, and cant remember how to solve that! the other guys (grant) looks right.