MATH Calc help! Find the area enclosed by the graphs of y=x^3+1x^2-2x+1 and y=2x^2-1x+0.?

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2007-06-05 03:27:39 · 3 answers · asked by chris s 1 in Science & Mathematics ➔ Mathematics

Trivially, it's infinite or unbounded (on either side of the origin) unless you get some endpoints into the question ☺

Doug

2007-06-05 03:33:30 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋

area
= â«|(x^3+1x^2-2x+1)-(2x^2-1x+0)| dx, x from -1 to 1
= 4/3
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Ideas: Find the intersection points first.

2007-06-05 10:40:19 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋

All you gotta do mate is intergrate it. That is add one to the power then divide by it...

Answer is 1/4x^4+1/3x^3-x^2+x+c dx
and 2/3x^3-1/2x^2+c dx

2007-06-05 10:45:23 · answer #3 · answered by Anonymous · 0⤊ 0⤋