this is part of my revision
2007-05-29 23:29:28 · 9 answers · asked by Queenie 4 in Science & Mathematics ➔ Mathematics
by the way 2/3 was a fraction. and it was a minus fraction.
2007-05-29 23:44:32 · update #1
Basically, you have to break down the power into pieces.
[Note: Using the rule which stated: X^(a*b) =(X^a)^b.]
(125)^(-2/3)
= [125^(1/3)]^(-2)
~> Since 125 = 5^3, 125^(1/3) = 5
=(5^2)^-1
=1/25
2007-05-29 23:33:35 · answer #1 · answered by Ben 3 · 0⤊ 0⤋
= 1 / 125^(2/3)
= 1 / 5²
= 1 / 25
= 4 / 100
= 0 . 04
2007-05-30 07:22:47 · answer #2 · answered by Como 7 · 0⤊ 0⤋
knowing powers of integers will help
for example 125 = 5^3 so 125^(1/3) = 5
so (125)^(-2/3) is 5^(-2) = 1/25
2007-05-30 06:35:54 · answer #3 · answered by TENBONG 3 · 0⤊ 0⤋
125^(-2/3)
= 1/[125^(2/3)]
= 1/[cube root of 125]^2
= 1/(5^2)
= 1/25
2007-05-30 20:53:43 · answer #4 · answered by Kemmy 6 · 0⤊ 0⤋
=(125)^-2/3
=1/(125)^2/3
=1/(*cuberoot of* 125)^2
=1/(5)^3
=1/25
2007-05-30 06:38:33 · answer #5 · answered by EJ Maximo 2 · 0⤊ 0⤋
(125)^-2/3
=1/(125)^2/3 ........(a^)-m = 1/a^m
=1/(5^3)2/3 ........1/(a^m)^n =1/a^mn
=1/5^2
=1/25
2007-06-02 06:04:58 · answer #6 · answered by billako 6 · 0⤊ 0⤋
if it x (a number) to the power of a/b, i look at it his way. b root of
x the power of a.
i.e 3rd root of 125 =5
5 to the power of 2= 25.
Good luck on Monday. i'm sitting the exam too
2007-05-30 16:58:24 · answer #7 · answered by manunitedk 3 · 0⤊ 0⤋
(125)^-2/3
=(5^3)^-2/3
=(5)^3*-2/3
=(5)^-2
=1/5^2
=1/25
2007-05-30 06:37:31 · answer #8 · answered by Jain 4 · 0⤊ 0⤋
It's imperative that you know the basic meaning of the concept!!!!!!!
2007-05-30 06:34:14 · answer #9 · answered by Dave B 2 · 0⤊ 0⤋