and get 15?
or can you not do that for imaginary numbers?
Sqrt(-1) = i = imaginary number, to remind you folks.
2007-05-29 20:13:56 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
we get (sqrt 15) i
2007-05-29 20:16:12 · answer #1 · answered by swd 6 · 2⤊ 0⤋
are you asking if the square root of 15 multiplied by i equals 15?
No.
any number x times i will equal xi. sqrt(15) times i will equal i ⋅ sqrt(15), which can be written sqrt(-15). Thats a far cry from a full positive, real 15
2007-05-29 21:04:38 · answer #2 · answered by Anonymous · 1⤊ 0⤋
yes you can but the answer would be an imaginary number sqrt(15)*i.
2007-05-29 20:16:52 · answer #3 · answered by Mock Turtle 6 · 2⤊ 0⤋
You can multiply, but the product is not 15.
The product can be expressed as
sqrt(-15)
or
i * sqrt(15)
2007-05-29 20:20:19 · answer #4 · answered by ? 6 · 2⤊ 0⤋
sqrt(-1) * sqrt(15) = sqrt(15)i ;
it is impossible to get 15 as the answer
2007-05-29 20:19:50 · answer #5 · answered by Anonymous · 2⤊ 0⤋
√(-1) = i
√(-1) x √15 = i.√15 = √(15) i
2007-05-29 20:19:27 · answer #6 · answered by Como 7 · 2⤊ 0⤋
sqrt(15) i
2007-05-29 21:23:28 · answer #7 · answered by fii 3 · 1⤊ 0⤋