A loudspeaker is connected to a spring (spring constant k = 15.9 N/m) as shown in the figure below. The speaker moves back and forwards in simple harmonic motion with an amplitude of A = 0.77 m. The mass of the speaker is m = 100 g.
What is the maximum speed of the speaker?
The answer is 9.71 m/s , but I dont know how to get it, Thanks for your help :)
2007-05-29 19:55:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The equation of motion is s = A*sin(w*t), where w is the angular frequency and is given by
w = √[k/m]
The velocity is ds/dt = A*w*cos(w*t). The maximum is then A*w, or
Vmax = A*√[k/m]
Plug in your values for A = 0.77m, k = 15.9 N/m and m = 100g and you will get your answer.
2007-05-29 20:09:43 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
for maximum speed all potential energy in spring should be converted into kinetic energy
1/2k*A^2=1/2 m*v^2
2007-05-29 20:01:18 · answer #2 · answered by tarundeep300 3 · 0⤊ 0⤋