That is 4 x squared minus 25 = 0 I am trying to find the work to solve this
2007-05-29 19:24:30 · 9 answers · asked by ttttwo_finger 1 in Science & Mathematics ➔ Mathematics
4x^2-25=0
move 25 over to the other side
4x^2=25
divide both sides by 4
x^2=25/4
take the square root
x = 5/2
x = -5/2
2007-05-29 19:27:53 · answer #1 · answered by anonymous_20003 3 · 0⤊ 0⤋
4x^2 - 25 = 0
Move the -25 to the right hand side.
4x^2 = 25
Divide both sides by 4,
x^2 = 25/4
Now take the square root of both sides, _keeping in mind_ that we have to use the square root property and include both plus and minus.
x = +/- 5/2
Therefore,
x = {-5/2, 5/2}
2007-05-29 19:28:33 · answer #2 · answered by Puggy 7 · 0⤊ 0⤋
add 25 for both sides
4x^2 = 25
divide 4 for both sides
x^2 = 25/4
take a square root
x = +/- sqrt(25/4)
x = 5/2 or -5/2
2007-05-29 19:29:09 · answer #3 · answered by 7 · 0⤊ 0⤋
There are two waysto solve this problem.
Method 1
4x^2-25=0
4x^2-5^2=0
(2x+5)(2x-5)=0
2x+5=0 or 2x-5=0
2x=-5 or 2x=5
x=-5/2 # or x=5/2#
Method 2
4x^2-25=0
4x^2=25
x^2=25/4
x=(+/-)sqrt(25/4)
=+/-5/2#
2007-05-29 19:40:45 · answer #4 · answered by jackleynpoll 3 · 0⤊ 0⤋
4x^2-25 = 0
4x^2 = 25
x^2 = 25/4
x = +- 5/2
2007-05-29 20:10:13 · answer #5 · answered by wanda 3 · 0⤊ 0⤋
4x^2-25=0........+25 to both sides
4x^2=25.........take square root of both sides
4x=5........divide both sides by four
x=5/4
2007-05-29 19:32:54 · answer #6 · answered by Michael M 2 · 0⤊ 0⤋
4x² = 25
x² = 25 / 4
x = ± (5 / 2)
2007-05-29 19:46:48 · answer #7 · answered by Como 7 · 0⤊ 0⤋
4x² - 25 = 0
4x² = 25
2x = ± 5
x = ± 5/2
Doug
2007-05-29 19:34:14 · answer #8 · answered by doug_donaghue 7 · 0⤊ 0⤋
(2x+5)(2x-5)=0
x= 5/2 or x=-5/2
2007-05-29 21:24:22 · answer #9 · answered by fii 3 · 1⤊ 0⤋