Is this a perfect square, a difference of squares, or a sum of squares? and how can it be factored.
49a^2-42ab+9b^2
2007-05-29 15:46:19 · 7 answers · asked by Anonymous in Education & Reference ➔ Homework Help
49a^2-42ab+9b^2 can be factored into
(7a-3b)(7a-3b)
is a perfect square
2007-05-29 15:49:26 · answer #1 · answered by mshaw70123 2 · 0⤊ 0⤋
very easy.
by just lookin' at it, you'd reckon that it is a perfect square..
think of any factor that would result to 49 and 3.
For this instance, you'd get only 2 sevens for 49, and 2 threes for 9.
thus, factorization would be like this...
(7a - 3b) (7a - 3b) or (7a-3b)^2
use the F.O.I.L (first, outside, inside, last)method to check the equation if ever you have some doubt.
Good luck!
2007-05-29 22:54:17 · answer #2 · answered by edelweiss 2 · 0⤊ 0⤋
dis is a perfect square because
49a^2 - 42ab + 9b^2
=49a^2 - 21ab -21ab +9b^2
=7a(7a - 3b) -3b(7a -3b)
=(7a -3b)(7a - 3b)
i hope i was able to help
2007-05-29 22:56:40 · answer #3 · answered by Olayemi E 1 · 0⤊ 0⤋
(7a - 3b)^2 = 0
It's a perfect square.
2007-05-29 22:49:36 · answer #4 · answered by tkquestion 7 · 0⤊ 0⤋
Sum of squares
(7a - 3b) * (7a - 3b)
2007-05-29 22:48:58 · answer #5 · answered by pjd4gnr 2 · 0⤊ 0⤋
(7a-3b)(7a-3b)
i am goooood
2007-05-29 22:54:33 · answer #6 · answered by Denise the great 3 · 0⤊ 0⤋
ok baby.
2007-05-29 22:48:21 · answer #7 · answered by private0909 1 · 0⤊ 1⤋