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How do you solve cot(23)^-1? I've seen questions like cot^-1(23), but not one where the -1 is after. Is it the same? I feel like an idiot.

2007-05-29 15:37:50 · 3 answers · asked by kathryn 2 in Science & Mathematics Mathematics

I guess I did mean the latter, but the problem just says "find the value of cot(23)^-1. and yes it's degrees

2007-05-29 16:04:12 · update #1

3 answers

cot^-1(23) = [cot(23)]^-1.

cot(23)^-1 = cot(1/23).

2007-05-29 15:44:08 · answer #1 · answered by Mark 6 · 0 0

1. You are NOT an idiot! The usage of indices with trig functions is confusing.
2. "cot^-1 (...)" (or arcot, or arccot ...) means the inverse function, whereas with any positive integer, n, in place of -1 it means the nth power of the cot value.
3. The given expression is ambiguous: it could mean cot (23^(-1)), or (cot 23)^(-1) -- probably the latter is intended.
4. IMPORTANT NOTES:
(a) Did you mean 23 degrees? As it stands, without indication of units, radians is implied. (23 radians is nearly 6 full turns!)
(b) You SOLVE an equation; you EVALUATE an expression.

2007-05-29 15:55:27 · answer #2 · answered by Keith A 6 · 0 0

1/ 23^1

1/ 23

2007-05-29 15:41:27 · answer #3 · answered by Anonymous · 0 1

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