Write an equation for the lin in slope-intercept form SEE BELOW?

Question

Passing through (2,2) and perpendicular to the line whose equation is y=1/8x + 3.

Please help homework questionl.

Answer 1

Perpendicular lines have negative reciprocal slopes, so the new line will have slope -1/(1/8) = -8.

It will be:

y = -8x + b

All lines of that form are perpendicular to a line with slope 1/8. Now you just need to plug in the point (2,2) to solve for b:

y = -8x + b
2 = -8*2 + b
2 = -16 + b
18 = b

Which means that the equation for the perpendicular line that passes through that one point is:

y = -8x + 18

Answer 2

y=1/8x + 3

m = 1/8

the slope of a perpendicular line with respect to the other line is

m' = -1/m

m' = -1/(1/8) = -8

using the slope intercept-form eqn:

(y-y1) = m(x-x1)

at pt (2, 2), x1 = y1 = 2

y - 2 = -8 (x -2)
y - 2 = -8x + 16
y = -8x +18

Answer 3

y=-8x + 18