In order to solve this problem:
A^(2C)/B^(4D) x B^3/ A^2
would I cross multiply and the divide each side by the b when I set it up as an equation or would I just add the numerators together? Any help would be appreciated.
2007-05-29 15:10:15 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A^(2C) x B^3
----------------
B^(4D) x A^2
A^(2C) x A^(-2)
------------------
B^(4D) x B^(-3)
A^(2C-2)
----------
B^(4D-3)
thats it. :)
2007-05-29 15:16:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
There is no = sign so there is no cross multiplying and no equation.
(A^(2C) / A²) x (B³ / B^(4D))
= A^(2C - 2) x B^(3 - 4D)
= A^2.(C - 1).B^(3 - 4D)
2007-05-29 20:14:07 · answer #2 · answered by Como 7 · 0⤊ 0⤋
(By "solve this problem", do you mean "simplify this expression"?)
"To multiply powers of the same base, add the indices; to divide, subtract."
You get: A^ (2C-2) * B^(3-2D); which = A^ (2C-2) / B^(2D-3)
2007-05-29 15:18:40 · answer #3 · answered by Keith A 6 · 0⤊ 0⤋
(a^2c)(b^3)/(4d)(a^2)
ab^6c/4da^2
b^6/4da
2007-05-29 15:16:01 · answer #4 · answered by Anonymous · 0⤊ 1⤋