Earlier I asked a similar question...but I still don't get the problem, please help..click?

Question

Use the laws of exponents to simplify...(a^4/5 times b^5/12)^6

The question earlier was (a^2/3 times b^7/10)^5 and the correct answer given to me was a^10/3 b^7/2.

I understand how they got the a^10/3 (because you multiply 2 times 5 =10 therefore 10/3) but how did they get the 7/2?

Answer 1

(a^x)^y = a^(x*y)

(a^(4/5)b^(5/12))^6 =
a^(4/5 * 6)b^(5/12 * 6) =
a^(24/5)b^(30/12) =

New law: a^(x/y) = a^(x-y)
a^19 * b^18


Original problem"
(b^(7/10))^5 =
b^((7/10) * 5) = b^(7/2)

And actually, that's b^5. The answer should be a^7b^5

Answer 2

they got the 10/3 by doing 2/3 times 5. They got the 7/2 by doing 7/10 times 5, which makes 35/10, or 7/2

on this new one, it would be a^24/5 b^5/2
4/5 times 6 gives you the 24/5
5/12 times 6 gives you 30/12, or 5/2

Answer 3

a^24/5 * b^30/12

a^24/5 * b^5/2

ab^120/10

ab^12