(6x-4)squared =42 and 4xsquared +5x =-3 can any one show me the steps to solve?

Answer 1

Take sq rt

6x - 4 = + - sq rt 42
6x = 4 + - sq rt 42
x = (4 + - sq rt 42) / 6

4x^2 + 5x + 3 = 0
(2x + 3)(x + 1) = 0

2x + 3 = 0, 2x = -3, x = -3/2
x + 1 = 0, x = -1

Answer 2

For the first one, take the square root of both sides, and you get:

6x-4 = sqrt(42)
Now, solve for x, and you get:
6x=sqrt(42) + 4 or
x=[sqrt(42)+4]/6

As for the second one, first get it into the quadratic form:

4x^2+5x+3 = 0

Now, this does not factor nicely, so you need to use the quadratic formula. When you have ax^2+bx+c=0, the formula is:

[-b+/- sqrt(b^2-4ac)]/2a

So, in this case, you have:

[-5 +/- sqrt(5^2 - (4)(4)(3))]/(2)(4) or
[-5 +/- sqrt(25-48)]/8 or
(-5 +/- sqrt(-23))/8 or
(-5 +/- i*sqrt(23))/8

(note that sqrt(-1) = i)

Answer 3

well 6x-4 = 42 is easy

first add the oppist of -4 to bolth sides 6x-4(+4)=42(+4)
next devide the new 46 by 6 6x = 46
6 6
that leaves x by itself and now u get x= 7.6
repeeting or rounded u get 7.7

sorry about the next one i havent done that kind in so long i cant remember the other

Answer 4

integrate the like words (7a and 2a): 9a - 4 = 3a -2 upload 4 to the two fringe of equation: 9a = 3a + 2 Subtract 3a from the two facets: 6a = 2 Divide by skill of 6 on the two facets a = 2/6 = a million/3

Answer 5

Question 1
36x² - 48x + 16 = 42
18x² - 24x - 13 = 0
x = [24 ±√(576 + 936)] / 36
x = [24 ± √(1512)] / 36
x = 39.6 , x = - 0.41
Question 2
4x² + 5x + 3 = 0
x = [- 5 ± √(25 - 48) ] / 8
x = [- 5 ± √(- 23)] / 8
x = [- 5 ± (√23) i] / 8

Answer 6

42+4=48 48/6x=8 and i don't get the second one. sorry