factor trinomial
16yex2 + 40y + 25=
2007-05-29 13:29:22 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Hi,
(4y + 5)^2 or (4y + 5)(4y + 5)
I hopr that helps!! :-)
2007-05-29 13:36:30 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
I presume 16yex2 is supposed to be 16 * y squared.
That's more commonly written as 16y^2.
16y^2 + 40y + 25 = 0
This factors nicely into:
(4y + 5)^2 = 0
If you want to finish up and solve the problem, it turns out that 4y+5 = 0, so y = -5/4.
Hope that helps!
2007-05-29 13:39:01 · answer #2 · answered by Bramblyspam 7 · 0⤊ 0⤋
i am not sure u wrote the q right it has to be :
16y^2+40y+25=(5+4y)^2
2007-05-29 13:36:55 · answer #3 · answered by n.h 3 · 0⤊ 0⤋
16y^2+40y+25
=(4y)^+2*4y*5+(5)^2
=(4y+5)^2
2007-05-29 13:37:09 · answer #4 · answered by alpha 7 · 0⤊ 0⤋
(4y+5)(4y+5)
2007-05-29 13:37:12 · answer #5 · answered by simply-remember 5 · 0⤊ 0⤋
i got y = -7.025
2007-05-29 13:41:15 · answer #6 · answered by Anonymous · 0⤊ 0⤋