What is the positive root of the equation 3x^2 + 5x = 8?

Answer 1

First, let's rearrange this into:
3x^2 + 5x -8 = 0

This factors rather neatly into:
(3x + 8) * (x - 1) = 0

So the two roots are where 3x+8 = 0 and where x-1 = 0
In other words, x = -8/3 and x = 1

Hence, the positive root is x = 1.

Answer 2

3x^2 +5x -8=0
(3x +8) (x-1) =0
roots are 1 and -8/3
1 is the positive root

Answer 3

Just looking at it, I can see that the answer is 1
(3 + 5 = 8).

But they probably expect you to show some work.
If we write the equation as 3x^2 + 5x - 8 = 0
Then we have A = 3, B = 5, C = -8 for the good old
quadratic equation:

X = (-B +/- SQRT(B*B-4*A*C))/2A

or X = (-5 +/- SQRT(25+96))/6
or X = (-5 +/- SQRT(121))/6
or X = (-5 +/- 11)/6
or x = 6/6 or -16/6
or x = 1 or -8/3

If you were meant to factor the equation, then

(X-1)(3x+8) are the factors.

Answer 4

3x^2 + 5x = 8 subtract 8 from each side
3x^2+5x-8=0
(3x+8)(x-1)=0 since you want only the positive root
x-1=0 add 1 to each side
x=1

The negative root can be found from
3x+8=0 subtract 8 from each side
3x=-8 divide both sides by 3
x=-8/3

Answer 5

well you still need to know how to do it
move eight over to other side so 3x^2 + 5x -8= 0
when you factor you get ( 3x+8) ( x-1)= 0

x= -8/3 x= 1 plug it in and it works. Still if you didn't know how to factor use quadratic formula.

I hope I didn't just do your hw..lol.. I still need to find the answer to MY question..

Answer 6

3x^2 + 5x - 8 = 0

x = -5 + - sq rt (25 - 4(3)(-8)) / 2(3)

x = -5 + - sq rt(121)/6

x = -5 + - 11 / 6

Positive root 6/6 = 1

Answer 7

it is one you have to factor x then u get x(3x+5)=8
and two numbers that u need 1*8=8