What quantityof 2.00M sodium hydroxide would be needed to neutralize 10.0mLof 1.00M hydrocholric acid?

Answer 1

M1 x V1 = M2 x V2

(V1) x (2.00 M) = (10.0 mL) x (1.00 M)

V1 = (10.0 mL*M) / (2.00 M)

V1 = 5.00 mL