help HURRY HURRY ASap?

Question

Factor 2x2 - 7x - 15.
A) (2x + 1)(x - 15)

B) (2x - 15)(x + 1)

C) (2x + 3)(x - 5)

D) (2x - 3)(x + 5)

Answer 1

Its C

Answer 2

We will factor this quadratic expression by grouping:

2x^2 - 7x - 15

= 2x^2 - 10x + 3x - 15 replace the middle term with terms that sum to the product fo the first and last term

= 2x(x - 5) +3 (x - 5) factor two terms at a time

= (2x + 3)(x - 5) factor out the common binomial factor

So, 2x^2 - 7x - 15 = (2x + 3)(x - 5)

Answer 3

Factor the expression 2x^2-7x-15

First: multiply the 1st & 3rd terms to get (-30). find two numbers that give you (-30) when multiplied & (-7)/2nd term when added/subtracted. the numbers are (-10 & 3).

Sec: rewrite the expression with the new middle terms.

2x^2 - 10x + 3x - 15

Third: with 4 terms - group "like" terms & factor both sets of parenthesis.

(2x^2 - 10x) + (3x - 15)

2x(x - 5) + 3(x - 5)

(x-5)(2x+3) or, (2x+3)(x-5)

Answer 4

The answer is C. Shame on you college student.
Clearly (2x+3)(x-5) = 2x^2 -7x -15.

Answer 5

Answer C.
(2x + 3)(x - 5)

Answer 6

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Answer 7

c is the answer are u writing a test

Answer 8

i confirm C

Answer 9

C

Answer 10

C