x^4 + 5x^3 - 14x^2
= x^2 (x^2 +5x -14)
= x^2 (x+7)(x-2)
A
2007-05-29 08:15:55
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answer #1
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answered by MsMath 7
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The answer is A
x^4 + 5x3 - 14x2.
= x^2(x^2+5x-14)
= x^2(x+7)(x-2)
2007-05-29 08:19:06
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answer #2
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answered by ironduke8159 7
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usually the easiest way to figure these problems out is to take out the most x as possible first. In this case it is x^2....then your left with x^2+5x-14. From here i always look at just the number part (-14) and get the factors (1,14) and (2,7) from here all you have to do is find the combination that makes a -14 and a +5.
ans: A) x^2(x + 7)(x - 2)
P.S. this doesnt always work hence the quadratic equation but thats a different story...
2007-05-29 08:40:47
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answer #3
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answered by flames_187 1
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x^4 + 5x3 - 14x2
= x^2 ( x^2 + 5x - 14)= x^2(x + 7)(x - 2)
2007-05-29 08:17:33
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answer #4
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answered by pioneers 5
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x^4 + 5x^3 - 14x^2.
=x^2(x^2+5x-14)
=x^2(x+7)(x-2)#
2007-05-29 19:32:45
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answer #5
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answered by jackleynpoll 3
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we can ingredient this quadratic expression by employing grouping: 2x^2 - 7x - 15 = 2x^2 - 10x + 3x - 15 replace the middle term with words that sum to the product fo the 1st and final term = 2x(x - 5) +3 (x - 5) ingredient 2 words at a time = (2x + 3)(x - 5) ingredient out the person-friendly binomial ingredient So, 2x^2 - 7x - 15 = (2x + 3)(x - 5)
2016-10-06 06:33:42
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answer #6
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answered by ? 4
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The answer is ....
McDonalds !!!
If this fails, you can still get a job at Burger King ...
2007-05-29 08:21:49
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answer #7
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answered by Ted 2
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do your own homework, this is a place to ask for help, not to have someone else do it for you
2007-05-29 08:15:17
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answer #8
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answered by Anonymous
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this is a tough one
2007-05-29 08:15:56
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answer #9
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answered by Philip G 1
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A
2007-05-29 08:20:38
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answer #10
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answered by DASHARK21 2
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