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Factor completely x^4 + 5x3 - 14x2.
A) x^2(x + 7)(x - 2)

B) x(x^4 + 5x^3 - 14x^2)

C) x(x2 + 5x - 14)

D) x^2(x - 7)(x + 2)

2007-05-29 08:12:43 · 12 answers · asked by Anonymous in Science & Mathematics Mathematics

12 answers

x^4 + 5x^3 - 14x^2
= x^2 (x^2 +5x -14)
= x^2 (x+7)(x-2)
A

2007-05-29 08:15:55 · answer #1 · answered by MsMath 7 · 1 1

The answer is A
x^4 + 5x3 - 14x2.
= x^2(x^2+5x-14)
= x^2(x+7)(x-2)

2007-05-29 08:19:06 · answer #2 · answered by ironduke8159 7 · 0 0

usually the easiest way to figure these problems out is to take out the most x as possible first. In this case it is x^2....then your left with x^2+5x-14. From here i always look at just the number part (-14) and get the factors (1,14) and (2,7) from here all you have to do is find the combination that makes a -14 and a +5.

ans: A) x^2(x + 7)(x - 2)

P.S. this doesnt always work hence the quadratic equation but thats a different story...

2007-05-29 08:40:47 · answer #3 · answered by flames_187 1 · 0 0

x^4 + 5x3 - 14x2
= x^2 ( x^2 + 5x - 14)= x^2(x + 7)(x - 2)

2007-05-29 08:17:33 · answer #4 · answered by pioneers 5 · 0 0

x^4 + 5x^3 - 14x^2.
=x^2(x^2+5x-14)
=x^2(x+7)(x-2)#

2007-05-29 19:32:45 · answer #5 · answered by jackleynpoll 3 · 0 0

we can ingredient this quadratic expression by employing grouping: 2x^2 - 7x - 15 = 2x^2 - 10x + 3x - 15 replace the middle term with words that sum to the product fo the 1st and final term = 2x(x - 5) +3 (x - 5) ingredient 2 words at a time = (2x + 3)(x - 5) ingredient out the person-friendly binomial ingredient So, 2x^2 - 7x - 15 = (2x + 3)(x - 5)

2016-10-06 06:33:42 · answer #6 · answered by ? 4 · 0 0

The answer is ....

McDonalds !!!

If this fails, you can still get a job at Burger King ...

2007-05-29 08:21:49 · answer #7 · answered by Ted 2 · 0 0

do your own homework, this is a place to ask for help, not to have someone else do it for you

2007-05-29 08:15:17 · answer #8 · answered by Anonymous · 0 1

this is a tough one

2007-05-29 08:15:56 · answer #9 · answered by Philip G 1 · 0 0

A

2007-05-29 08:20:38 · answer #10 · answered by DASHARK21 2 · 0 0

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