These are the measurements of my lot (125 ft. wide on both ends, 345 ft. deep on the upper end and 332.50 ft. on the lower side) Please explain to me how you calculate the answer. Thanks.
2007-05-29 07:00:15 · 3 answers · asked by Jay 2 in Science & Mathematics ➔ Mathematics
.97 is what the court house told me. I calculated it to be 1.24. Then I went to the building inspector and they pulled my lot up by a system called GSI and it also showed 1.24 (this is why I am confused)
2007-05-29 07:24:51 · update #1
An acre is 4,840 yds² or 43,560 ft²
Now you can do the math. Sounds as if your lot is a trapezoid.
The parallel sides of a trapezoid are called the bases.
The height of the trapezoid is the perpendicular distance between the bases.
The area of the trapezoid is equal to the average of the bases times the height. So, you add the two bases, divide by 2, and then multiply by the height. This would be:
area = ((b1 + b2) / 2)h
2007-05-29 07:07:53 · answer #1 · answered by Robert L 7 · 0⤊ 0⤋
Can't be sure without knowing shape of your land.If it is approximately rectangular use the formula for the area of a trapezeum.
You get Area =(345+332.5)/2 X125 square feet=42344 sqr.ft =4705 square yards.
An acre =4840 square yds.
You have about 97percent of an acre (if the shape is nearly a rectangle.
2007-05-29 07:37:32 · answer #2 · answered by L D 6 · 0⤊ 0⤋
The area is 125 * (345 + 332.50 ) / 2 ft^2
= 125 * (345 + 332.50 ) / ( 2 * 43560 ) acre
= 0.972 acre.
A little short of an acre.
2007-05-29 07:12:48 · answer #3 · answered by Anonymous · 0⤊ 0⤋