calculate the stress applied to the wire havng mass per unit length 0.1 g/cm and density 7 g/cm^3, when 10 gm wt is attached to itz free end. answer =6.86x 10^4 N/m^2. plz try ths one for me dudes....intellegnt minds plz
2007-05-29 06:43:14 · 2 answers · asked by khushal g 1 in Science & Mathematics ➔ Physics
divide linear density by density to get area of cross section. multiply it to 10^4 so it becoms in m^2. now divide 10*10^-3*9.8 by area of cross section to get result.
thanks
2007-05-29 21:27:38 · answer #1 · answered by C.Bhartiya 3 · 0⤊ 0⤋
first you need cross section area of wire. from mass/length a 1cm length weighs .1g, and from density 7g/cm^3 must have volume of .1/7=.0143.
since L=1cm and vol=LxA, area = .0143/1 = .0143cm^2
stress is force per unit area, so (10gx9.81m/s^2) /.0143cm^2
adjust units to match (0.010kgx9.81m/s^2)/ (0.00000143m^2)
= 68,601 N/m^2
2007-05-29 07:17:04 · answer #2 · answered by Piglet O 6 · 0⤊ 0⤋