(3 marks)
this is from my revision paper, please can you show me how to work it out.
2007-05-29 06:36:30 · 9 answers · asked by FoYSoLa1 1 in Science & Mathematics ➔ Mathematics
y^2 + 5y = 0
y^2 = 0 - 5y
y^2 = -5y (divide by y both sides)
y = -5
TO CHECK
(-5)^2 + 5(-5) = 0
25 - 25 = 0
2007-05-29 06:47:41 · answer #1 · answered by nothingspecial 1 · 0⤊ 0⤋
y^2+5y=0
y(y+5)=0 (factoring the above)
This means y=0 or y+5=0
y+5=0 gives y=-5 (subtract 5 from both sides)
so y=0 or y=-5
2007-05-29 13:42:37 · answer #2 · answered by cidyah 7 · 0⤊ 0⤋
y^2 + 5y = 0
y(y+5) = 0
So
y = 0 or y+5 = 0
y = 0 or -5
2007-05-29 19:45:29 · answer #3 · answered by Kemmy 6 · 0⤊ 0⤋
I cannot correct spelling of matematics.
I express the equation like this:
y2+5y=0
y(y+5)=0
The roots are: y= 0 ore y= -5
You can put in the numbers in the equation and control.
2007-05-29 17:11:11 · answer #4 · answered by anordtug 6 · 0⤊ 0⤋
y (y+5) = 0
y =0 or y=-5
y = -5
always remember to check your answers against the original equation:D
2007-05-29 13:41:16 · answer #5 · answered by Vacinando 3 · 0⤊ 0⤋
y^2 + 5y = 0
y(y+5)=0
y=0 or y=-5
2007-05-30 03:06:47 · answer #6 · answered by jackleynpoll 3 · 0⤊ 0⤋
y^2 + 5y = 0
y * (y + 5) = 0
In that case or y=0, or y+5=0
So there are 2 answers:
1. y=0
2. y=-5
2007-05-29 13:41:58 · answer #7 · answered by grinww91 1 · 0⤊ 1⤋
y^2 + 5y = 0
Therefore, y(y + 5) = 0
Therefore, y = 0 or y = -5
Hope this helps.
2007-05-29 13:40:29 · answer #8 · answered by Anonymous · 0⤊ 0⤋
y.(y + 5) = 0
y = 0 , y = - 5
2007-05-29 15:39:10 · answer #9 · answered by Como 7 · 0⤊ 0⤋