algebra 2 help?

Question

Use the quadratic formula to solve each equation.

12x^2 - 5x - 7 = 0

Answer 1

quadratic formula

x = - b ± √b² - 4ac / 2a

12x² - 5x - 7 = 0

a = 12, b = - 5, c = - 7

x = - (- 5) ± √(- 5)² - 4(12)(- 7) / 2(12)

x = 5 ± √25 - (- 336) / 24

x = 5 ± √25 + 336 / 24

x = 5 ± √361 / 24

x = 5 ± 19 / 24

- - - - - - - -

Solving for +

x = 5 + 19 / 24

x = 24 / 24

x = 1

- - - - - - - - -

solving for -

x = 5 - 19 / 24

x = - 14 / 24

x = - 0.5833333333. . .

- - - - - - - -s-

Answer 2

If ax^2 + bx + c = 0, then

x = (-b +or- sqrt(b^2 - 4ac))/(2a).

Given 12x^2 - 5x - 7 = 0.

Let a = 12, b = -5, and c = -7.

x = (-(-5) +or- sqrt((-5)^2 - 4(12)(-7))/(2(12))

x = (5 +or- sqrt(25 + 336))/24

x = (5 +or- sqrt(361))/24

x = (5 +or- 19)/24

x = (5 + 19)/24 or (5 - 19)/24

x = 1 or -7/12

Answer 3

I can't remember off the top of my head but this is a polynomial that needs to be factored...Try this site that I found by googling.