Theoretically, a single point. Like the ones you use to graph in math. Infinitesimally small.
2007-05-29 08:14:38
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answer #1
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answered by Anonymous
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A singularity has no size. Just like the corner of a sheet of paper has no size, the center of a circle has no size, or the South Pole has no size. When we do solutions to some of Einstein's field equations with regard to gravity, space, etc., we get solutions for a singularity...a point of zero volume containing infinite mass. Clearly nonsense!
In the case of a black hole's singularity, that doesn't mean the matter is no longer there. It is just in a form that we know nothing about. It's beyond all theories that we currently have which describe matter, energy, and spacetime.
2007-05-29 13:41:07
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answer #2
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answered by Chug-a-Lug 7
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Basically, one singularity is the same size as two singularities.
So the big question is how large are an infinite number of singularities?
2007-05-29 13:38:04
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answer #3
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answered by Lorenzo Steed 7
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A singularity is a point size and so theoretically will be 0 sized.
2007-05-29 13:29:58
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answer #4
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answered by Swamy 7
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I assume you are talking about in "science" terms as opposed to mathematics. A gravitational singularity does not have a "size". It is a point, without dimension.
http://en.wikipedia.org/wiki/Gravitational_singularity
2007-05-29 13:28:46
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answer #5
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answered by Dan K 3
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It's the same size as it was the last 5 times you asked.
2007-05-29 13:35:04
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answer #6
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answered by tastywheat 4
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In theory, the size is not quantifiable, rather the term refers to a single point from which everything eminates. If you are looking for a numerical value it would be 1.
2007-05-29 13:34:33
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answer #7
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answered by Compurednek 3
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I think I remember reading that if a black hole was formed from a star 50 times the mass of the sun, the event horizon (which I suspect you are thinking of) would extend to a diameter of 3km.
2007-05-29 13:31:10
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answer #8
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answered by langdonrjones 4
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Anything smaller than the Planc length cannot be measured and that would include a black hole.
2007-05-29 13:44:19
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answer #9
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answered by Anonymous
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