Find the discriminant of each quadratic equation.
-10x^2 - 6x + 5 = 0
2007-05-29 06:11:04 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
ax^2 + bx + c = 0
Discriminant = b^2 - 4ac
Here a = -10
b = -6
c=5
There discriminant = (-6)*(-6) - 4*(-10)*(5)
=36 + 200 = 236
2007-05-29 06:17:28 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Discriminant (D) = b^2-4ac where in your case:
a = 10, b= -6 c = 5
So D = (-6)^2 -4(-10)(5)
D = 36 + 200 = 236
2007-05-29 13:24:13 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
10x² + 6x - 5 = 0
x = [- 6 ± â(36 + 200) / 20
x = [- 6 ± â(236) / 20
Discriminant is â236 = 2.â59
2007-05-29 14:07:03 · answer #3 · answered by Como 7 · 0⤊ 0⤋
The discriminant is the sqrt(b^2 - 4ac) part of the quadratic formula.
2007-05-29 13:15:00 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(-6)^2 - 4(-10)(5) = 236
2007-05-29 13:16:54 · answer #5 · answered by lgr_86 1 · 0⤊ 0⤋