2007-05-29 05:28:17 · 17 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(what?+5)/3=x
2007-05-29 05:31:02 · answer #1 · answered by theclassclown01 1 · 0⤊ 1⤋
Assuming the question was really:
3x+-5= 0
add 5 to each side:
3x = 5
divide each side by 3:
x = 5/3
2007-05-29 12:31:44 · answer #2 · answered by Lobster 4 · 0⤊ 0⤋
x = 5/3
2007-05-29 12:31:05 · answer #3 · answered by Anonymous · 0⤊ 1⤋
x = 5/3
2007-05-29 12:30:35 · answer #4 · answered by Anonymous · 1⤊ 2⤋
3 x + - 5 = what
3x - 5 = what
3x-5 +5 = what +5
3 x = what + 5
3x/3 = what + 5 / 3
x = what + 5 /3
2007-05-29 12:41:19 · answer #5 · answered by jon_mac_usa_007 7 · 0⤊ 0⤋
3x + -5=0 to solve this, first move the -5 to the right hand side of the equation, which will make it positive
3x = 5
next simply divide both sides by 3 in order to cancel out the 3 on the left hand side (3/3=1)
(3x)/3=5/3
so now we are left with
x=5/3
this is your final answer, but you can also write it as 1 and 2/3 or as a decimal 1.66666667
2007-05-29 12:34:22 · answer #6 · answered by robot love 2 · 0⤊ 1⤋
first, add 5 to both sides
3x -5+5=5
subtract
3x=5
divide both sides by 3
x =5
____
3 = 3
x= 5/3
2007-05-29 12:35:52 · answer #7 · answered by ~*LEAH*~ 2 · 0⤊ 1⤋
Hi,
For this question, you need to isolate for x by first adding 5 to both sides of the equation. Your work should look like the following:
3x = 5 <====Result after adding 5 to both sides of equation
x = 5 / 3 <=====Result after dividing by 3 on both sides of previous equation. FINAL ANSWER
I hope that helps you out! Please let me know if you have any other questions!
Sincerely,
Andrew
2007-05-29 12:35:22 · answer #8 · answered by The VC 06 7 · 0⤊ 1⤋
3x+-5 = 3x-5
2007-05-29 12:29:56 · answer #9 · answered by Anonymous · 1⤊ 1⤋
3x+(-5)=?
switch sides for the answer.
-3X+5
2007-05-29 12:31:36 · answer #10 · answered by neohacker22000 2 · 0⤊ 1⤋