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I have this first one i believe.. but i am not sure if it is the correct answer.

1) 25 divided by square root (15)
I was able to get 125 / 3 or 41.7


2.) 3rd root (x^6 y^7) divided by 3rd root (9)


3.) 3 square root (50) + square root (24) - 2 square root (18)


4.) 18 divided by square root (5) - 3 square root (5)


If you could please help.. Not sure how to add and subtract square roots♥

2007-05-29 04:59:41 · 7 answers · asked by Anonymous in Science & Mathematics Mathematics

7 answers

I have this first one i believe.. but i am not sure if it is the correct answer.

1) 25 divided by square root (15)
I was able to get 125 / 3 or 41.7

Ans: 25/sqrt.15 = 25/sqrt.(3x5) = 5sqrt.5/sqrt.3

Please note that square root of 15 is a little less than 4 (4 is the square root of 16). So, 25 divided by 4 will be 6.25 and 25 divided by square root of 15 will be a little more.

2.) 3rd root (x^6 y^7) divided by 3rd root (9)

Without knowing x and y, there is no solution

3.) 3 square root (50) + square root (24) - 2 square root (18)

3 X 5 X sqrt.2 + 2 sqrt.(2 X 3) - 2 X 3 X sqrt.2 = 9 sqrt2 + 2 sqrt 6

4.) 18 divided by square root (5) - 3 square root (5)

18/sqrt.5 - 3.sqrt.5 = (18 - 15) / sqrt.5 = 3/sqrt.5


If you could please help.. Not sure how to add and subtract square roots♥

2007-05-29 05:12:02 · answer #1 · answered by Swamy 7 · 0 0

A good calculator will help you find the square root of any non-negative number. If you don't have a real one you can use the one that's in your computer.

2007-05-29 05:03:23 · answer #2 · answered by PumpkinEater 4 · 0 0

i just finished algebra 1-2 in 7th grade. we just touched a little bit on square roots, and here's what i know:

1: 25 times the square root of 15
_________________________
15

(That is supposed to be a fraction thingy)

2. ????????????? didn't learn it

3.18 times the square root of 2 plus the sqrt of 6 minus the sqrt of 2

4. i dk

4.

2007-05-29 05:13:29 · answer #3 · answered by ~*LEAH*~ 2 · 0 1

So what precisely are you attempting to do? I see a collection of numbers which may be solved on the calculator and written in any different case. Are you attempting to simplify it? Or is there some lacking tips?

2016-11-23 14:27:41 · answer #4 · answered by ? 4 · 0 0

your making errors everywhere...

get a secondary level math book and look up the chapter titled 'surds', shouldn't take you more than an hour to be able to answer these questions correctly for yourself if you just study the examples.

2007-05-29 05:03:39 · answer #5 · answered by Anonymous · 0 0

adding and subtracting is easy
squrt(2)+squrt(2)=2squrt(2)
squrt(2)-squrt(2)=0
as long as they have the same numbers under the root your good if its like
squrt(2)+squrt(5)= squrt(2)+squrt(5)

2007-05-29 05:05:55 · answer #6 · answered by zspace101 5 · 0 0

1) 25/sqrt15 = 25/ 3.873
= 6.45

2) (x^6y^7)^1/3/(9^1/3)=
((x^6y^7)/9)^1/3

3). 3sqrt50 +sqrt24-2sqrt18=
3* 7.11 + 4.9 -2* 4.24=
21.33 +4.9 -8.48=
17.75

4.)(18/sqrt5)-3sqrt5=
(18-15)/sqrt5=
3/sqrt5=
3/2.236 =
1.34

2007-05-29 05:18:12 · answer #7 · answered by bignose68 4 · 0 1

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