Choose the correct prime factorization of 56.
A) 7 × 8
B) 2 × 33
C) 23 × 7
D) 6 × 9
2007-05-29 04:43:10 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
it has to be c) 2 ^ 3 * 7 = 8 * 7 = 56
2007-05-29 04:46:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
None of the above. The prime factorization of a number is the multiplication of prime numbers that produces the number. For A) 8 is not prime. For B), 2 x 33 is 66 so thats out ... for C) 23 x 7 is 161 and for D) neither 6 or 9 is prime.
The actual prime factorization is 2^3 x 7
2007-05-29 04:49:26 · answer #2 · answered by Dan G 2 · 0⤊ 0⤋
56= 2*28 = 2*2*14 = 2*2*2*7 = 2^3*7 which is answer C
Good luck
If answer C is 2 to the 3rd times 7. If it is, it might be better written as 2^3 not 23 (as some may be confused that that number is twenty three :l )
2007-05-29 04:47:16 · answer #3 · answered by A confused bio student 2 · 0⤊ 0⤋
Prime factors of 56
56 / 2 = 28
28 / 2 = 14
14 / 2 = 7
7 / 7 = 1
56 = 2 x 2 x 2 x 7
2 x 2 x 2 = 8
8 x 7 = 56
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2007-05-29 05:04:57 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
no answer. the numbers have to be prime numbers
2 x 2 x 2 x 7
2007-05-29 04:48:56 · answer #5 · answered by R 2 · 0⤊ 0⤋
none of the above
56 = 2^3 * 7
2007-05-29 04:46:10 · answer #6 · answered by SS4 7 · 0⤊ 0⤋
2 x 2 x 2 x 7
None are correct, but A is the best answer
2007-05-29 04:46:24 · answer #7 · answered by zeb 4 · 0⤊ 0⤋
none of the above
2007-05-29 04:45:39 · answer #8 · answered by fcas80 7 · 0⤊ 0⤋
no answer
2007-05-29 04:46:20 · answer #9 · answered by Anonymous · 0⤊ 0⤋