a mass hanging from a vertical spring and a simple pendulum each have a period of oscillation of 1 sec. If you were to take these devices to another planet where the acceleration due to gravity is greater than on earth, would the period of each device be greater than 1 sec , less than 1 sec, or the same? why?
2007-05-29 03:09:11 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The period of oscillation for a simple pendulum is 2*PI*SQRT(l/g). If g increases, then the period decreases and will be less than 1 sec.
For a spring system T = 2*PI*SQRT(k/m). This is g independent, therefore it is still 1 sec.
2007-05-29 03:17:37 · answer #1 · answered by dudara 4 · 0⤊ 0⤋
Since the restoring force of gravity is higher on the planet, the period will be less than 1 sec.
2007-05-29 03:17:50 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
It will be less than 1 second.
Formula for simple pendulum is-:
time period = 2 * pi * sqrt(length / accel. due to gravity)
If the accel to gravity increases, the time period will decrease.
2007-05-29 03:16:23 · answer #3 · answered by Doctor Q 6 · 0⤊ 0⤋