2007-05-29 02:59:51 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-i :)
2007-05-29 03:15:56 · answer #1 · answered by A confused bio student 2 · 1⤊ 1⤋
1/i =
1•i / i•i =
i / -1 =
-i
2007-05-29 03:03:27 · answer #2 · answered by Philo 7 · 1⤊ 2⤋
1 / i = i / i² = - i
2007-05-29 03:30:07 · answer #3 · answered by Como 7 · 0⤊ 3⤋
1 / i
= 1*i / i*i
= i / (-1)
= -i
2007-05-29 03:03:53 · answer #4 · answered by Mathematica 7 · 0⤊ 3⤋
It's -i, since -i*i = 1.
2007-05-29 03:04:02 · answer #5 · answered by TFV 5 · 2⤊ 2⤋
what, do you mean 1/1??? its 1
2007-05-29 03:03:29 · answer #6 · answered by ღßutterflyღ 3 · 0⤊ 6⤋
Hi,
Recall i = square root of -1
Therefore, we have 1 / sqr.(-1)
Now, you can rationalize the denominator by saying:
[1 / sqr.(-1) ] [ sqr.(-1) / sqr.(-1) ]
sqr. (-1) / -1
i / -1
FINAL ANSWER ====> - i
I hope that helps! Please let me know if you have any other questions!
Sincerely,
Andrew
2007-05-29 04:44:19 · answer #7 · answered by The VC 06 7 · 0⤊ 2⤋
Let me complicate your life just a little more.
i = exp(i*π/2)
1/i = i^(-1) = exp(-i*π/2)
= cos(-π/2) + i*sin(-π/2)
= 0 - i
2007-05-29 03:11:50 · answer #8 · answered by Dr D 7 · 0⤊ 3⤋
-i
2007-05-29 03:04:39 · answer #9 · answered by Anonymous · 1⤊ 2⤋