so..bascially how do you find the componenet form of this vector: plese show me how! (the process or steps involved).
This is all they give, now wants us to convert this into componenet form of a vector. How do you do it?
llvll=8, theta=120 degrees.
2007-05-29 02:58:14 · 4 answers · asked by hellokid 1 in Science & Mathematics ➔ Mathematics
So we want a vector of length 8 that points in the direction of theta = 120 degrees. Convert 120 degrees to 2pi/3 radians. We know the sin and cos of 2pi/3 radians. Construct a right triangle with the vector as the hypotenuse and the x-axis as one leg, so the second leg is parallel to the y-axis. The length of the hypotenuse is given; use trig to find the lengths of the legs. Those are your x and y components of the vector. The solution will be (x,y), where x and y are the lengths.
Another approach that does essentially the same thing (with less drawing) is to realize that they have given you a point in polar coordinates, with r = 8. You can use the equations that convert polar to rectangular. Those equations come directly from the right triangle method, but if you have them already, you can just use them instead.
2007-05-29 03:12:48 · answer #1 · answered by TFV 5 · 0⤊ 0⤋
Horizontal component
x = 8.cos 120°
x = - 4
Vertical component
y = 8.sin 120°
y = 8.√3 / 2
y = 4.√3
2007-05-29 03:34:26 · answer #2 · answered by Como 7 · 0⤊ 0⤋
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2016-10-30 01:56:39 · answer #3 · answered by ? 3 · 0⤊ 0⤋
It's simply
v_x = |v|*cosθ
v_y = |v|*sinθ
2007-05-29 03:18:40 · answer #4 · answered by Dr D 7 · 0⤊ 0⤋