from 1 to 0
(x2 - 2x)dx
2007-05-29 02:06:02 · 5 answers · asked by chetzel 3 in Science & Mathematics ➔ Mathematics
I can really get the extra practice on integrals, I have nothing better to do, while you sit down and just get the answer!!!
2007-05-29 02:11:54 · answer #1 · answered by Anonymous · 1⤊ 2⤋
One of the primitives of x^2 - 2x is x^3/3 - x^2. So, to find the integral from 1 to 0 (that's how you put it) you compute this primitive at 0 and at 1 and subtract. You get 0 -(1/3 - 1)= 2/3.
2007-05-29 02:20:59 · answer #2 · answered by Steiner 7 · 0⤊ 2⤋
integral of x^2-2x
= x^3/3 - x^2
as it is definite integral constant of integration shall cancell.
at 1 it is 1/3-1 = -2/3
at 0 is zero
so integral from 0 to 1 = -2/3
2007-05-29 02:09:59 · answer #3 · answered by Mein Hoon Na 7 · 1⤊ 2⤋
int(x^2 - 2x) dx = [x^3/3 - 2x^2/2] = [x^3/3 - x^2]
[1^3/3 - 1^2] - [0^3/3 - 0^2] = [1/3 - 1] - [0 - 0]
= -2/3-0 = -2/3
inegrate and than subract the lower bound by the upper bound
2007-05-29 02:10:28 · answer #4 · answered by A confused bio student 2 · 0⤊ 2⤋
integral of xpower 2 is (x 3)/3
integral of 2x is x2/2
so answer is
(x3/3)-2(x2/2) = (x3/3)-x2
now enter values of x
u will get answer
2007-05-29 02:13:20 · answer #5 · answered by ss 4 · 1⤊ 0⤋