How many G's does a top fuel dragster pull in the first second.?

Question

I think the average is around 4 G's.
330 mph in a quarter mile. This is a calculus analysis.

Answer 1

Simplest answer -- assuming no wind resistance

s = (1/2) a t^2
a = dv/dt = v(final)/ t
so
(2s)/v(final) = t = 5.53s

dv/dt ~ (330mph)/(5.53s) = 87.4 ft/s^2

87.4/32 = 2.7G

So 4G in the first second is reasonable.

Thats the average over the whole time. If you want the first second, you will need to assume something like drag increasing with the square of the velocity -- then set up an ODE around the force balance. And that will be a better approximation using calculus.

dv/dt = accleration - kv^2/m
where k is an unknown drag form factor and will likely no be needed since you start at 0 velocity and you know your final velocity and the distance traveled.
v(nought) = 0
v(final) = 330mph
s = 1/4mile = v(t)*t

Answer 2

In order to exceed 300 MPH in 4.5 seconds, dragsters must accelerate an average of over 4 G's. In order to reach 200 MPH well before half-track, the launch acceleration approaches 8 G's.