density of gold, which is: 19.3 g/cc
--- http://www.google.com/search?hl=en&q=gold+density
(12 inch) * (12 inch) * (12 inch) = 28316.8466 cc
--- http://www.google.com/search?hl=en&safe=off&q=12+inch+*+12+inch+*+12+inch
(28 316.8466 cc) * 19.3 (g / cc) = 546.515139 kilograms
--- http://www.google.com/search?hl=en&safe=off&q=28316.8466+cc+*+19.3+g%2Fcc&btnG=Search
2007-05-22 06:34:27
·
answer #1
·
answered by DanE 7
·
0⤊
1⤋
I got to hold a real gold ingot during a VIP gold-mine tour. It was only about 12" x 4" by 1.5" (IIRC) and the sucker weighed 75 lbs!
At the time, it was worth US$275,000 -- most money I've ever held in my hands at one time (let alone seen, at one time).
.
2007-05-22 14:19:31
·
answer #2
·
answered by tlbs101 7
·
0⤊
0⤋
you need to know the thickness in order to calculate the weight. Her is an on-line calculator. Make sure you choose the right drop down lists pertaining to each entry such as naterial (gold) inches vs centimeters
http://www.matweb.com/tools/weight-calculator.asp
2007-05-22 13:42:39
·
answer #3
·
answered by kathleen 7
·
0⤊
0⤋
you have a square foot (12 x 12) and no third dimension given. as such the third dim is infinite and so would be the weight...merci. what a heavy thing! and you thought there was no answer! tricky question,eh! watson?
2007-05-22 13:50:16
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
100 X (Thickness of the block in inches) ( units lbs)
2007-05-22 14:04:32
·
answer #5
·
answered by apm2006 3
·
0⤊
0⤋
uh, zero? It has no height, only length and width.
2007-05-22 13:31:08
·
answer #6
·
answered by 006 6
·
1⤊
0⤋