how much frequency (in hertz) do you expect to get from a simple lc circuit?

Question

just wondering

and is it me or do these formulas don't work
(i converted them and they displayed nothing similar to any examples i were given)
according to lessons in electric circuit in their chapter for resonance they had a formula they worked out with an lc circuit and they had an outcome different from mine how can this be here it is

1/2pi sq rt(LC)

where
L=100mH
c=10uf

the outcome was
159.155HZ
i tried that on a scientific calculator and i came out with something completely different whats the deal am i doing something wrong
heres the site
http://www.ibiblio.org/obp/electricCircuits/AC/AC_6.html

Answer 1

f = 1/(2π√(LC)
f = 1/(2π√((100*10^-3)(10*10^-6))
f = 1/(2π√(0.000001)
f = 1/(2π(0.001))
f = 1/(0.006283185)
f = 159.1549 ≈ 159.155

I got a different result when I overlooked the m in mH.

Answer 2

a solid occasion of a circuit with the two DC and AC reaction is got here across in the operational amplifier. yet you do no longer think of of it as an AC circuit or a DC circuit that has an working frequency. quite, you think of of it as an amplifier whose bandwidth extends from DC to a frequency that's measured in Hertz. At DC, the frequency is 0.

Answer 3

Be sure that you have the correct formula for determining resonance frequency:

Fr= 1/((2Xpi)X(square root of (LC))) Next, convert 100 mh to h; and then convert 10 microfarads to Farads.

100 mh = 0.1 h
10 microfarads = 0.000,010 Farads.

Thus, Fr= 1/((6.28)X(square root of (0.100 h X 0.000,010)))

Fr = 159.24 Hz

Hope that helps

Answer 4

Helmut got the answer. The values must be entered as Henries and Farads.

Answer 5

don't know