Given f(x)=3x^2 + 2x + 7
find f(x)=0
2007-05-18 20:19:04 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
0 = 3x^2 + 2x + 7
It turns out there is no value of x for which the equation above holds true.
2007-05-18 20:25:43 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Substitue 0 in all x in the equation
f(0)=3(0)^2+2(0)+7
f(0)=7
because the numbers mutiplied by 0 are all 0 therefore the answer is 7
2007-05-19 03:51:51 · answer #2 · answered by musiclover2008 3 · 0⤊ 0⤋
Complex solution:
x=-1/3+(2/3)root(5)i or x=-1/3-(2/3)root(5)i
2007-05-19 03:33:04 · answer #3 · answered by phpiano 1 · 0⤊ 0⤋
3x² + 2x + 7 = 0
x = [ - 2 ± â(4 - 84) ] / 6
x = [ - 2 ± â(- 80)] / 6
x = [- 2 ± 4â(5) i ] / 6
x = (1/3).[ -1 ± 2â5 i ]
2007-05-19 03:51:52 · answer #4 · answered by Como 7 · 0⤊ 0⤋
Yup. Graph does not cut the x axis so there's no value where f(x) = 0...
2007-05-19 03:30:10 · answer #5 · answered by iyiem 2 · 0⤊ 0⤋
to resolve this , you will need to find delta which
b.b - 4ac = 2.2 - 4.3.7= 4 - 84= -80
since delta is negative , it's impossible to put f(X) in factors
we can conclude that we can't resolve for all R
2007-05-19 03:30:20 · answer #6 · answered by jay b 4 · 0⤊ 0⤋