What is the y-intercept of the line described by the equation 2y=5x-8? (please show steps)?

Question

What is the y-intercept of the line described by the equation 2y=5x-8? (please show steps)

Answer 1

The y-intercept is the point at which x=0
Set x=0 and solve

2y = 5(0) -8
2y = -8
y = -4

Answer 2

The general equation for a straight line is y = mx + c where m is the gradient and c is the y-intercept. Since you need to find the x-intercept you use the fact that all points on the x axis are y = 0 So if y = 0 then in y = -8x+ 3 we substitute y for 0 So 0 = -8x+3 Add 8x to both sides 8x = 3 Divide both sides by 8 x = 3/8 or 0.375 the x intercept is (0.375,0)

Answer 3

2y = 5x - 8
Make the equation in the form
y = mx + b

2y = 5x - 8
2y/2 = 5x/2 - 8/2

y = 5x/2 - 4
y-intercept is the value you get when x is set to zero, which is also the "b" in our equation
y = 5(0)/2 - 4
y = 0 - 4
y = -4 ==> the y-intercept

Additional info,
the slope is the coefficient of x, which is 5/2 or 2 1/2 or 2.5

Answer 4

To find the x-intercepts, let y=0 ==> solve for x
To find the y-intercepts, let x=0 ===> solve for y

2y=5x-8 ===> let x = 0
2y = 5(0) - 8
2y = -8 ==> divide by 2
y = -4

y-intercept (0, -4)
--------------------------------------------
or you can put it into slope-intercept form
y = mx + b ==> where m is slope and b is y-intercept
2y=5x-8 ==> divide by 2 to get y=
y = 5/2 x - 4

b = -4

y-intercept (0 , -4)



=]

..

Answer 5

Cuts y axis when x = 0
2y = - 8
y =- 4
Cuts y axis at (0 , - 4)

Answer 6

divide the whole thing by 2 and you get
Y=(5/2)X-4
and the y-intercept is -4

Answer 7

for the y-intercept, set x = 0

2y = -8
y = -4

Answer 8

Graph it.
Also set x=0 and see what the value of y is.