(8 x ^4 y ^2 + 3 x y - 10 y ^5) - (3 x ^4 y ^2 - 10 xy + 6 y ^5)
2007-05-18 18:04:05 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5x^4y^2+13xy-16y^5
2007-05-18 18:07:25 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
5x^4y^2 + 13xy - 16y^5
8 x ^4 y ^2 + 3 x y - 10 y ^5 - 3 x ^4 y ^2 +10 xy - 6 y ^5
=8 x ^4 y ^2- 3 x ^4 y ^2+ 3 x y+10 xy -10 y ^5- 6 y ^5
2007-05-19 01:07:38 · answer #2 · answered by Nana 3 · 0⤊ 0⤋
5x^4y^2+13xy-16y^5 Just subtract those with similar variables and exponents Also, remember PEMDAS, Parenthesis, Exponents, Multiplication, Division, Addition, and then Subtraction.
P.S. How do you get a best answer for this kind of question? I'm going to tell a math joke to try to get one. What did the lines do when it started to rain?
Coincide lol
What do you call Pythagoras's tea pot?
Hypotenuse Hy-pot-en-use lol
2007-05-19 01:21:18 · answer #3 · answered by The Doctor 2 · 0⤊ 0⤋
Multiply the (-1) by the second trinomial and combine like terms
=8x^4y^2-3x^4y^2+3xy-(-10xy)-10y^5-6y^5
=5x^4y^2+13xy-16y^5
2007-05-19 01:20:47 · answer #4 · answered by Crystal 6 · 0⤊ 0⤋
(8x^4y^2 + 3xy - 10y^5) - (3x^4y^2 - 10xy + 6y^5)
To do this subtarction,
first change the sign of second terms inside the parenthesis
(8x^4y^2 + 3xy - 10y^5) - 3x^4y^2 + 10xy - 6y^5
Then add similar terms
8x^4y^2 + (-3x^4y^2) = 5x^4y^2
3xy + 10xy = 13xy
-10y^5 - 6y^5 = -16y^5
And combine them
5x^4y^2 + 13xy - 16y^5 ==> the answer
2007-05-19 01:18:27 · answer #5 · answered by detektibgapo 5 · 0⤊ 0⤋