(2y^7 m^-4)^5
the choices i have to choose from are
32y^12 / m^-1
32y^-35 / m^20
32y^35 / m^20
all of these
none of these
2007-05-18 17:36:13 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
apply th exponent 5 to every factor
2^5 * y^35 m^-20
32y^35 / m^20
2007-05-18 17:38:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Remember these identities for exponents
(x^m)^n = x^mn (meaning you have to multiply the power)
x^ -m = 1/x^m
(2x^7 m^-4) ^5 =
(2^5)(x ^7*5)(m^ -4 *5) =
32 x^35 m^-20 =
32x^35/m^20
Third choice
2007-05-19 01:01:14 · answer #2 · answered by detektibgapo 5 · 0⤊ 0⤋
The seconds one,
remember you multiply since the exponenet affects everything in the parantheses.
2007-05-19 00:39:25 · answer #3 · answered by Jelli 1 · 0⤊ 0⤋
32y^35 / m^20
Now get busy and learn the rules of exponents âº
Doug
2007-05-19 00:40:19 · answer #4 · answered by doug_donaghue 7 · 0⤊ 0⤋
32y^35 / m^20
2007-05-19 00:41:29 · answer #5 · answered by Jamie 2 · 0⤊ 0⤋
Third one, Megan!
2007-05-19 00:41:05 · answer #6 · answered by migpanviq 1 · 0⤊ 0⤋