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What errors in concentration are introduced when only dilution is taken into account by using only dilution equation- M1V1=M2V2

2007-05-18 17:09:11 · 3 answers · asked by Alan l 1 in Science & Mathematics Chemistry

3 answers

M1 = the concentration of the 'mixer'
V1 = the volume of the 'mixer'
M2 = the concentration of the 'mixed with'
V2 = the volume of the 'mixed with'

If the liquid is already mixed before equation, M1=M2

2007-05-18 17:14:11 · answer #1 · answered by Daniel J 2 · 0 0

If you have a very concentrated acid or base, you will get an exothermic reaction when water is added to dilute it.

If the resulting solution is very warm, then the volume of the solution may be slightliy larger than the volume that you would get at room temperature.

As a rule, solutions that may generate excessive heat should be cooled in an ice bath for safety when prepared. Also, you should wait until the solution has reached room temperature before verifying the final volume.

Other errors can occur when mixing two solutions that are very miscible, as alcohol and water. A classic demonstration of this phenomenon is to add 100 mL ethanol to 100 mL water, which will give you something like 195 mL of solution. The reason is that water and alcohol form hydrogen bonds with each other, and fill in the spaces in between molecules, so that there is a slight contraction of the final volume.

2007-05-18 17:19:29 · answer #2 · answered by mrfarabaugh 6 · 1 0

I don't understand your question. The dilution equation is supposed to account for dilution assuming that the diluent (pure solvent added to the initial solution) is actually pure solvent.

2007-05-18 17:14:26 · answer #3 · answered by cattbarf 7 · 0 0

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