At t = 0, a 765 g mass at rest on the end of a horizontal spring (k = 130 N/m) is struck by a hammer, which gives it an initial speed of 2.71 m/s.
Determine the period of the motion.
s
I used T= 2(pi) sqrt(k/m)
2007-05-18 15:18:34 · 3 answers · asked by sleepy 1 in Science & Mathematics ➔ Physics
Hehehe. Try
T = 2π√(m/k) = 81.9 s
It always helps to use the correct equation ☺
Doug
2007-05-18 15:39:55 · answer #1 · answered by doug_donaghue 7 · 0⤊ 0⤋
It's just the opposite:
T=2*Pi*SQRT(m/k)
As you can see in order to determine the period the value of velocity is unnecessary. It would be need if, for instance, you needed to calculate the amplitude of the movement.
In this case
T=2*Pi*SQRT(0.765/130) sec = 0.482 sec
2007-05-18 23:51:15 · answer #2 · answered by fanis t 2 · 0⤊ 0⤋
its actually
T= 2(pi) sqrt(m/k)
T= 2(pi) sqrt(.765kg/ 130N/m)
T= .481991s
Rememeber the units!!
kg/(n/m)= s
Hope this helps!
2007-05-18 22:44:32 · answer #3 · answered by frizzball2me 1 · 0⤊ 0⤋