2007-05-18 08:22:38 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
[14(a^3)(b^2)] / [21(a^5)(b^6)] =
[14/21]*[a^3 / a^5]*[b^2 / b^6] =
[2 / 3] * [1 / a^2] * [1 / b^4] =
2 / [3 * a^2 * b^4] =
(2/3) * a^-2 * b^-4
2007-05-18 08:29:00 · answer #1 · answered by Baselek 2 · 1⤊ 0⤋
14 a^3 b^2 / 21 a^5 b^6
2/3 a^-2 b^-4
2007-05-18 17:29:33 · answer #2 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋
[14(a^3)(b^2)] / [21(a^5)(b^6)]
divide numerator and denominator by 7
[2(a^3)(b^2)] / [3(a^5)(b^6)]
divide numerator and denominator by a^3
[2(b^2)] / [3(a^2)(b^6)]
divide numerator and denominator by b^2
2 /(3(a^2)(b^4)) or
(2/3)(a^-2)(b^-4)
,
2007-05-18 15:33:15 · answer #3 · answered by Robert L 7 · 1⤊ 0⤋
(2/3)*(a^(-2))*(b^(-4))
2007-05-18 15:28:13 · answer #4 · answered by Ali 1 · 1⤊ 0⤋
14a^3b^2 / 21a^5b^6
Divide 14 and 21 by 7
2 a^3b^2/3a^5b^6
Now, rule a^n/n^m=a^n-m
2/(3a^2b^4)
2007-05-18 16:06:40 · answer #5 · answered by danjlil_43515 4 · 1⤊ 0⤋