Can some one help solve the following Problems:Ln(x+12)-(x+4)=Ln2 or Ln(x+12)-Ln(x+4)=Ln2?

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Can some one help solve the following Problems:Ln(x+12)-(x+4)=Ln2 or Ln(x+12)-Ln(x+4)=Ln2?

2007-05-18 08:05:59 · 2 answers · asked by PAExpress 1 in Science & Mathematics ➔ Mathematics

2 answers

Two basic rules of logarithms

Ln(a) + Ln(b) = Ln(ab)
Ln(a) - Ln(b) = Ln(a/b)

So

Ln(x+12) - Ln(x+4) = Ln[(x+12)/(x+4)] = Ln(2)

(x+12)/(x+4) = 2

x+12 = 2x+8

x=4

2007-05-18 08:13:33 · answer #1 · answered by Astral Walker 7 · 1⤊ 0⤋

Ln(x+12)-Ln(x+4)=Ln2
ln((x+12)/(x+4)) =ln 2
(x+12)/(x+4) = 2
x+12 = 2x+8
x = 4

2007-05-18 15:36:45 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋