2007-05-18 07:38:18 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(5a -3b)(2a +4b)
Multiply each of the terms in the first bracket by the second bracket.
(5a -3b)(2a +4b)
= (5a)*(2a +4b) + (-3b)*(2a +4b)
= 10a^2 + 20ab - 6ab - 12b^2
= 10a^2 +14ab - 12b^2
Don't factor out anything here (such as 2, even though it would be correct and 'prettier'). The point was to expand the 2 brackets.
2007-05-18 07:40:59 · answer #1 · answered by Anonymous · 2⤊ 0⤋
You have (5a -3b)(2a +4b).
Now, if you expand out, you get:
5a*2a+5a*4b-3b*2a-3b*4b,
which is:
10a^2+20ab-6ab-12b^2
Simplify, you get
(5a -3b)(2a +4b) = 10a^2+14ab-12b^2
2007-05-18 07:40:23 · answer #2 · answered by Mox 2 · 2⤊ 0⤋
REMOVE THE BRACKETS
5a*2a + 5a*4b - 3b*2a - 3b * 4b= 10a2+20ab-6ab-12b2
=10a2+14ab-12b2
2007-05-18 07:50:52 · answer #3 · answered by preetha_jayakrishnan 1 · 2⤊ 0⤋
= 10a² + 20ab - 6ab - 12b²
= 10a² + 14ab - 12b²
= 2.(5a² + 7ab - 6b²)
2007-05-18 08:13:10 · answer #4 · answered by Como 7 · 0⤊ 0⤋
=10a^2+20ab-6ab-12b^2
=10a^2+14ab-12b^2
2007-05-18 07:45:45 · answer #5 · answered by shipdada 3 · 2⤊ 0⤋
its 2ab and 6 ab
2007-05-18 07:49:26 · answer #6 · answered by melikey2009 2 · 0⤊ 2⤋
use FOIL.... and watch your sign, then you shuld be fine.... =)
2007-05-18 07:42:11 · answer #7 · answered by L!LO 4 · 2⤊ 0⤋