Help With MATH PLEASE!!?

Question

1. If a=3 and b=3, find the length c rounded to the nearest hundreth.

2. If a= 16 and c= 20, find the length of b.

They are triangles.

Can You PLease Show Work. THANKS! =)

yes they both are right triangles

Answer 1

Assuming they are RIGHT triangles, use the Pythagorean Theorem:
a^2 + b^2 = c^2

1)
3^2 + 3^2 = c^2
9 + 9 = c^2
18 = c^2
sqrt 18 = c
4.24 = c

2)
16^2 + b^2 = 20^2
256 + b^2 = 400
b^2 = 144
b = 12

Answer 2

For both, just use a^2+b^2=c^2 (assuming these are RIGHT triangles)

1. 4.24

2. 12 (Note: you could recognize this as a classic multiple of the 3-4-5 right triangle)

Answer 3

I am assuming that you mean that they are right angled triangles where c is the hypotenuse.

Using Pythagoras...

a) sqrt(3^2 + 3^2) = 4.24

b) sqrt(20^2 - 16^2) = 12

Answer 4

1 = 4.24

2 = 12

Answer 5

if they are RIGHT triangles:

a^2 + b^2 = c^2

1)

a= 3
b= 3
c= ?

c = sqrt( 3^2 + 3^2 )
c = sqrt(18)
c = 3*sqrt(2)

2)
a= 16
b= ?
c= 20

b^2 = c^2 - a^2
b = sqrt( 20^2 - 16^2 )
b = sqrt ( 400 - 256 )
b = sqrt ( 144 )
b = 12

Answer 6

If they're right angle triangles then a^2+b^2=c^2 (with c being the longest side). However, if they're not triangles with right angles, then the angles are needed.

Answer 7

1. the information given is not sufficient to decide c. We need either all the three sides or two sides and the angle between them.

2. Same situation.

Answer 8

answers:

1) c=4.24
2) b=12

Answer 9

1. 6
2. 12

Answer 10

1. 5

2. 39