First, get the equation of the line into the slope-intercept form y = mx + b (i.e., express y):
5x-4y=-9
4y = 5x + 9
y = 5/4 x + 9/4
---> the slope of this line is 5/4 (and the y-intercept is 9/4)
---> any line parallel to this one will have the same slope!
=> slope of a parallel line: m = 5/4
---> The slopes m and n of two perpendicular lines satisfy the condition: m·n = -1
=> any line perpendicular to this line will have slope
m = -1 / (5/4) = -4/5
Hope this helps.
2007-05-18 05:46:51
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answer #1
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answered by M 6
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5x - 4y = -9
y = (-5x - 9) / -4
y = -5/-4 x - 9/-4
y = 5/4 x + 9/4
slope is 5/4 (all lines parallel)
Perpendicular lines are the negative reciprocal of the slope, which is -4/5 .
2007-05-18 12:52:02
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answer #2
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answered by Anonymous
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First, what is the slope of this line? Solve it for y.
4y = 5x + 9
or
y = 5/4 x + 9/4
So, this line and any line parallel to it will have a slope of 5/4.
Now, any line perp. to this line will have a slope that is -1 over this slope, also the negative recipricol or -4/5.
2007-05-18 12:49:32
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answer #3
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answered by tbolling2 4
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4y = 5x + 9
y = (5/4).x + 9/4
Perpendicular line has slope (- 4 / 5)
Parallel line has slope 5 / 4
2007-05-18 15:03:01
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answer #4
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answered by Como 7
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