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Give a formula for the coefficient of y^n in the expansion of (y + (2/y))^100, where k is a nonnegative integer.

2007-05-18 05:35:17 · 2 answers · asked by Ellabear 1 in Science & Mathematics Mathematics

2 answers

The general term in the expansion of
(y + (2/y))^100
is

(100 above k) · y^(100-k) · (2/y)^k =

(100 above k) · y^(100-k) · 2^k · y^(-k) =

100!/(100-k)!·k! · 2^k · y^(100-2k)

... are you told what exactly n should be?

Because if n = 50, say, than
100-2k should equal 50, i.e. k = 25 and then the term is

100!/75!·25! · 2^25 · y^50

and the coefficient of y^50 is 100!/75!·25! · 2^25.

2007-05-18 05:37:49 · answer #1 · answered by M 6 · 8 0

I would like to point out one missing detail from the very good first answer. Namely, k has to be an integer and hence the formula only gives the coefficient for EVEN values of n (= 100 -2k).

To make the answer complete, note that the coefficient for the y^n term is zero if n is an odd integer.

2007-05-18 10:54:51 · answer #2 · answered by chancebeaube 3 · 0 1

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